Zeit Probleme

Hallo,

hab ein Problem, mir schreibt er nun ständig vor 2 Stunde oder 11 Minute, wie kann ich das anderst machen das es "Deutsch" ist? ;) Außerdem schreibt er mir folgendes "vor 1.488593930548 Monat" möchte aber das nur "vor 1 Monat" angezeigt wird.

Der ursprüngliche Script:

	###
	function ago($time) {
	
	   $periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");  
	   $lengths = array("60","60","24","7","4.35","12","10");  
	   $now = time();

		   $difference     = $now - $time;
		   $tense         = "ago";  

		   for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
			   $difference /= $lengths[$j];
		   }
		   $difference = round($difference);
		   if($difference != 1) {
			   $periods[$j].= "s";  
		   }
	   return "$difference $periods[$j] ago";  
	}
}

habe hier schon angefangen umzuschreiben, bisher mit dem oben beschriebenen Fehlern.

	###
	function ago($time) {
	
	   $periods = array("Sekunde", "Minute", "Stunde", "Tage", "Woche", "Monat", "Jahr", "Jahrzehnt");  
	   $lengths = array("60","60","24","7","4.35","12","10");  
	   $now = time();

		   $difference     = $now - $time;
		   $tense         = "ago";  

		   for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
			   $difference /= $lengths[$j];
		   }
			if($difference != 1) {
			switch($difference) {
			case 0: // $periods
			case 1: // $periods[1]
			case 2: // $periods[2]
			case 4: // $periods[4]
			$periods .= 'n';  
			break;
			case 3: // $periods[3]
			case 5: // $periods[5]
			case 6: // $periods[6]
			$periods .= 'e';  
			break;
			case 7: // $periods[7]
			$periods .= 'en';  
			break;
			}
}
	   return "vor $difference $periods[$j]";  
	}
}

Please also mark the comments that contributed to the solution of the article

Content-Key: 225656

Url: https://administrator.de/contentid/225656

Printed on: April 16, 2024 at 21:04 o'clock

3 Comments

Latest comment

###
	function ago($time) {
	
	   $periods = array("Sekunde", "Minute", "Stunde", "Tag", "Woche", "Monat", "Jahr", "Jahrzent");  
	   $lengths = array("60","60","24","7","4.35","12","10");  
	   $now = time();

		   $difference     = $now - $time;

		   for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
			   $difference /= $lengths[$j];
		   }
		   $difference = round($difference);
		   if($difference != 1) {
                          if ($j <= 2 || $j == 4){
			     $periods[$j].= "n";  
                          } else{
                             $periods[$j].= "e";  
                          }
		   }
	   return "vor $difference $periods[$j]";  
	}
}

Grüße Uwe

Einwandfrei, vielen vielen Dank.

Keine Ursache.
Wenn's das dann war, den Beitrag bitte noch als gelöst markieren. Merci.

German solved Question PHP Development

Hotly discussed

End of Support dates for Office 2016, 2019 Apps und Productivity ServersDani - 1 Comment